# Please score this for me

### Scoring

I have 3 6's and one 3 How does that score?

### Three different ways of

Three different ways of making 6+6+3=15, that's 6 points
Three different pairs of sixes (pairs royal), that's another 6 points. Total 12.

### Three 6s and a 3 ???

Two 6s + the 3 = 15 for 2
Two other 6s + the 3 = 15 for 2
The last two 6s + the 3 = 15 for 2

Three 6s is three pair of 6s for 2 pts each.

Total 12 pts.

### There are three different

There are three different ways to score fifteen (9+3+3) - that's 6 points.

And there are three different pairs of 3's - that's Pairs Royal, another 6 points.

Total = 12 points.

### Hand points

I have 3 aces a jack and a 3 how many points possible, no nob

### 3 aces, a jack and a 3...

3 + two aces, 3 + two other aces, 3 + the last two aces all constitute 5s. Each going with the jack makes 15 for 2 three times for 6 pts.

The 3 aces make 3 separate pair of aces for 6 pts for a total of 12 pts.

3+3+9 = 15 for 2
3+3+9 = 15 for 4
3+3+9 = 15 for 6

and a triple(3+3+3) for 6

Total would be 12

### Crib Total

If I have a hand of 7-7-7-8 and an Ace comes up is that 18 or 24

### 8,7,7,7 + ace (up card)

8 + three 7s is 15 for 6
Three pair of 7s plus the ace with each one is 15 for 6
The pair of 7s is 2 pts each for 6

Total 18.

Where might the 24 come from? Did I miss something?

### What constiTues a run someone

What constiTues a run someone plays a 5 next person plays 3 next person plays 6 next person a 4 does this count as a run

### Flush argument between my wife and I.

Is it a flush if you have let's say 3 diamonds and a club in your hand. The starter card is also a diamond. Does that count as a flush? This isn't the crib.

### Flush me...

In your hand you must be holding 4 of the same suit for a 4 card flush. Five if the up card too. In the crib is must be all five for the flush.

### Not a flush. Must all 4 be

Not a flush. Must all 4 be in your hand. The crib must be all 5 cards to be worth anything.

### 3,3,3,4,9...

Three different pair of 3s + the 9 = three 15s for 6.
The three different pair of 3 equal 6 in pairs.

Total 12.

### crib

3333 6 how do you score this hand

### 3333 6

Score 20 points. 4 ways to make 15 + 12 for the quads.

### 6+3+3+3 = 15, this can be

6+3+3+3 = 15, this can be done four different ways so 8 point here.

Double Pairs Royal (four of a kind) is 6 distinct pairs, another 12 points.

Total 20.

### End of a turn

Hi

4 player game, players 1 & 3 have played out their cards. Player 2 plays last card ( a 5), player 4 plays a 5 - 10 for 2, then play their last card, also a 5, 15 for 2 plus 6 for the 3 x 5s, do you also get a point for it being the last card? We were told no as the last card was played on a scoring number (15), they stated its the same as finishing on 31?

Hope that makes sense!!

### Incorrect

You would get a go at the conclusion of the last card played. This is always a "go" as there are no other cards that can be played taking the score closer to 31. Just so you know 31 includes both a "go" and a bonus. That is why you don't get last card when hitting a 31 exactly. The "go" is already inside of a 31. Scoring to 15 does not have this and you should have taken a "go". It doesn't matter if it is played in a scoring sequence or not. Take your point. You earned it.

### Yes, there is also a point

Yes, there is also a point for last card.

### Runs

A sequence of 4-6-3-5 Is played. Does the playing of 5 count for a run of 4?

### Yes it does. The cards that

Yes it does. The cards that make the run don't have to be in order.

### Runs

Yes, it is an unbroken run score 4 points.

### Runs

4-6-3-5 count for 4

### Runs?

Claude are you asking if this is a run for four points? That would be correct.

### Three 4's and a 7. Please

Three 4's and a 7. Please score for me

### That's only four cards, so

That's only four cards, so I'll assume the fifth one is worthless...

4+4+7=15 three different ways, so that's 6 points.

Three distinct pairs of 4's = another 6 points.

Total = 12.

12 points

### score a hand

during play, we had a run that went 3,3,3,A,A,A,2
How do you score it for each player?

### 3 = 3 3 = 6 for 2 (pair) 3 =

3 = 3
3 = 6 for 2 (pair)
3 = 9 for 6 (three of a kind)
A = 10
A = 11 for 2 (pair)
A = 12 for 6 (three of a kind)
2 = 14

### Well....

First off we are missing a card. Since you only described 7 of them and there should have been 8. I am also assuming that you are asking about pegging and there are NO runs, so lets call P1 and P2 and see what they end up with.

p1 3 zero
p2 3 for 2
p1 3 for 6
p2 A for zero
p1 A for 2
P2 A for 6
P1 2 for zero
P2 ?

Looks like they both scored 8 points. Hope that helped!

### Scoring runs

Hand was 2-2-3-4 and the up card was a 2. We scored he hand 24.
Is this correct?

### Incorrect

This is a triple run with no 15's. Triple runs are always 15 without fifteens. 3 runs of 3 (9) plus trips (6). Always equals 15 unless fifteens are counted.

### Score 2-2-2-3-4

There are no 15s. So:
A run of 2-3-4=3
A 2nd run of 2-3-4=3
A 3rd run of 2-3-3=3
3 of a kind (2s)= 6
Score 15

### 2+2+3+4+2 = 13, so no points

2+2+3+4+2 = 13, so no points for fifteens are scored.

You have three runs of 3, that's 3x3=9.
Your three of a kind is three distinct pairs, for 3x2=6.

Total 15 points.

2,2,4,4 9

12?

### Yes

Correct Kimbereley

### Yes! Four different ways of

Yes! Four different ways of making 9+4+2=15, and the two pairs.

### i have 3 8's and 2 7's. score

i have 3 8's and 2 7's. score this for me please

### 20

3 eights and 2 sevens (or the other way around) is 20. (fifteen for 12, pair for 14 and trips for 20)

### You have six different ways

You have six different ways to make 15-2 (any of the three 8's with any of the two 7's).

So that's 2x6 = 12 for fifteens.

You also get 6 for the three 8's (Pairs Royal) and 2 for the pair of 7's.

Total = 12+6+2 = 20 points.

### 20 points

15s - 2,4,6 8,10,12
pair is 14
3 of a kind for 6 = 20

### Your score is 20. 15's x 6pts

15's x 6pts = 12pts

3 pairs of 8's = 6pts

1 pair of 7's = 2pts

### Peg point question

How do you score the peg points for this hand - at 29, player 1 lays an ace, player 2 plays an ace and then it’s a go at 30 and player 2 pegs 2 points (pair). Player 2 places another ace for 31. Does he then get to peg another 8 points, 6 for the 3 aces plus 2 for 31? Or is it just another 6 points (4 for the additional 2 aces plus 2 for the 31)? Thanks.

### Pegging

Please peg the points that you achieve in unbroken sequences. In the situation you describe, you would peg first two points for the pair, and then 6 additional points for the trips, and then 2 more for hitting 31 exactly. The best score you can make in this scenario is actually a lot more than that. Imagine of you were holding 7, A, A, A. The non-dealer is holding all face cards and another Ace. They lead a face card, you play a 7 for seventeen, they play another face card, you play an ace to 28, they play and ace to 29 for two, you play the next two aces, first one for 6 next one for 14. You just pegged 20 points and they pegged 3 (the pair and the last card of their remaining cards)

### Player 2 pegs another 8

Player 2 pegs another 8 points. You peg points every time a new card is played. Let's look at the sequence...

p1: ace, count=29
p2: ace for 2, count=30
p1: Go
p2: ace for 6 (three of a kind) + 2 for 31

### 4+4+4+3

How many 15's here ?