Pairs and triples

My opponent played his last card a five to add up to 21. I had two cards left, both fives. How does that peg?

Trips + 31

Assuming that we are only dealing with the 3 remaining fives, you would play one to 26 for two points and the last five to 31 for a total of 8 points. (6 for the 3-of-a-kind and two for 31 exactly.) This works with any combination of cards, not just 5's.

Answer to Pairs and Triples

In answer to this question: My opponent played his last card a five to add up to 21. I had two cards left, both fives. How does that peg?

Play your first five for 26, take 2 for the pair. Play your second five for 31, take 6 for the pair royal + 2 for 31.

26- pair for two on the first

26- pair for two on the first 5
31- triple for six, 31 for 8 on the second 5.

The first 5 give you a pair,

The first 5 give you a pair, for 2
The second 5 gives you a triple for 6 plus 1 for 2 more, totalling 8.

Pairs and triples

If, like you say, he has laid his last card (a Five) and you have two fives left, you peg like this.

You pair his five, making the total 26. You peg 2 for the pair.
Your opponent obviously cant go so you lay your second five, calling 31 and scoring 8 points for this card (6 for the triple and 2 for scoring 31). In total, you have pegged 10 pegs since he laid his final five

Total of 9

If your last two cards played are the same rank as the previous one played you would score 2 for a pair, 6 for trips and one for the last card (Go).