Here is a free online Cribbage game that I am developing. I have labeled it Crazy Cribbage as it has some really crazy options you can turn on to make game rather interesting. I would really appreciate some feedback.
It can be found at http://www.crazycribbage.com
When you are on the 2nd round of play, after reaching 31 or "go" to last card, does any sequencing continue when the count starts back over at zero?
Example of first sequence of card played: 5, 9, 7, 9
player 1 says "go" and player 2 cannot.
Play resumes with Player 1 putting down an 8
Does this count as a 3 card run, 7, 8, 9? or no, because when the count restarts at zero any pairs, runs, etc. also starts over?
Seems like double runs come in two flavors: a double run of 3 (e.g. 3-4-4-5 with any cut) or a double run of 4 (e.g. T-J-Q-Q with K cut).
I see two ways to score such a double 4-card run: as multiple 3-card runs, or multiple 4-card runs.
Example using the above TJQQK: either four 3-card runs (TJQ twice = 6 and JQK twice = 6) makes 12, and a pair is 14 total. Or, two 4-card runs for 8 (TJQK twice = 8), and a pair is only 10 total.
Wha? Which one is correct, and why? I'm just guessing I'm required to score this the second way. But I don't see why it should be one way or the other.
Reader Darren is looking for a cribbage board made by Ron Cyr called a "Cyrcle cribbage board". These seem to be quite rare and collectable, so if anyone owns or knows of such a board, please get in touch!
I am an avid cribbage player and have enjoyed the game for close to fifty years. I've never had a perfect twenty-nine hand but I've had three twenty-eight hands. I know that the odds of getting the twenty-nine hand are approximately one in a little over three million [ Actually, it's one in about 200,000 - Ed ]. Recently something very strange occurred to me. I dealt the first hand of a new game and here is how the scoring went:
The cut was not a jack
My regular hand yielded zero points
My crib hand yielded zero points
I have never heard of anyone else accomplish this feat. As you are aware the dealer of a hand will always score at least one point on a "go" or a "last card". So I am wondering - what are the odds of such an event occurring? I'm pretty decent with math problems however I'm not sure I even know exactly what equations are required to calculate the odds of getting a perfect "imperfect" hand. Can you help me figure out the end result?
To work out the odds of a zero-scoring cribbage hand (apart from the mandatory one point for go), we need to calculate how many such hands there are, and then divide that into the number of all possible cribbage hands. It is a tricky problem because we need to make no points in the play, assuming correct play. Anyone care to tackle it?