there is 15-2 15-4 15-6 and a triple run is a total of 21

I taught my 11 year old son to play a few weeks ago and he is really taken with the game.

On Sunday, he had an amazing hand and I want to make sure the I taught him how to score it correctly.

his hand: A 2 3 3
my hand: 2 3 3 4
cut: A

I lead the 3
he played his 3 to make 6 and peg 2 points
I played my 3 to make 9 and peg 6 points
he played his 3 to make 12 and peg 12 points,

so then there were 4 threes played in a row. I could play my 4 or 2, opening up the chance for a run.

I played my 2 for 14,
and he played his ace for 15, and 2 points, and a quadruple run, 3,3,3,3,2,A for 24 points!!

I played my 4 for 19
and he played his 2 for last card and a point,

so, he pegged 41 points!! is this correct??

and then I scored 10 for my double run

and he scored 16 for a double double run,

so he got 57 points, and I don't even remember what the crib was.

Did I mess up the scoring, or was this an incredible hand?

You are quite right. You can only count any given cards once. It doesn't matter if you arrange them in a different order, they are still the same cards, and they can only be used once in each combination to make 15.

By contrast, if you had, say, 6-6-3-3, then you could make 15 two ways: once with each of the 3s. You can use the 6s again this time, so long as you combine them with a different 3.

I have been fortunate to be dealt 2 29 hands in the last year.
The first was very conventional and was acknowledged by all.

The second was dealt to me and the hand was played, but my wife had first count and closed the game out. She contends that since I did not get to count the hand that it does not officially count as a 29 hand.
I contend that the hand was dealt and played and the fact that I was unable to count it was irrelavant.

I will be intersted in hearing form your constituents.

SRL in Michigan

I was playing a game with a friend and we ended up having the exact same hand! What are the odds? Actually, we had 5 of the 6 cards dealt the same (i.e. 4,5,6,7,8,9 & 3,5,6,7,8,9), but we discarded the odd one and were both left with 5,6,7,8. What are the probability of that happening?

Thanks,
Cal

the count would be 24, fifteen 12 once you make all the possible suit combinations with the threes plus 12 for the four of a kind
heart = club
heart = spade
heart = diamond
club = diamond
club = spade
diamond = spade

"How many 15's are in this count. I count 15's twice but I am told that you can only count the 3 cards one time. Is this true? My problem is if there was a third 6 that there is 3 15's. Why can I not count 2 15's with the 2 6's? "

I presume you are talking about counting the hand at the end of play. In that case, let's say you have 6-6-3-10 with K as your up card. This hand counts as 15-2 (6-6-3) and a pair for 4 (6-6). Remember, you are counting the UNIQUE combinations of cards adding up to 15. Let's look at your other example:

Hand is 6-6-6-3 with a K up card. It would help to label the cards, like so:
6S-6D-6C-3H, KS (Spades, Diamonds, Clubs, Hearts)

This hand counts as 15-6 and a triple for 6 more, for a total of 12 points in the hand. You can make 15 like so: 6S-6D-3H, 6S-6C-3H, 6D-6C-3H. Counting 6S-6D-3H and 6D-6S-3H as two combinations does not count; they are the same three cards.

This game sucks to log into, from the beginning that is.

can you tell me how to score a hand of 2,3,3,7?

someone plays all of his cards before the other person...does the person get a GO after each card??

What is the Point value for 3-3-4-5-5?

Just wanted to drop a quick note here that we have just released another update to the Cribbage Pro game for Android. Check the blog for a post on some of the details, but the major add is the new manual counting and muggins options.

Enjoy!
-- Josh